If x(1), x(2) ....... x(n) & (1)/(h(1)),...

If `x_(1), x_(2) ....... x_(n)` & `(1)/(h_(1)), (1)/(h_(2)) .....(1)/(h_(n))` are two such that `x_(3)=h_(2)=8` & `x_(8)=h_(7)=20` then `x_(5)h_(10)` is

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2560

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