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Let sum(k=1)^(10)f(a+k)=16(2^(10)-1), w...

Let `sum_(k=1)^(10)f(a+k)=16(2^(10)-1),` where the function f satisfies `f(x+y)=f(x)f(y)` for all natural numbers x, y and f(1) = 2. Then, the natural number 'a' is

A

2

B

3

C

16

D

4

Text Solution

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The correct Answer is:
B
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