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Let the sum of the first n terms of a non-constant A.P., `a_(1), a_(2), a_(3),... " be " 50n + (n (n -7))/(2)A`, where A is a constant. If d is the common difference of this A.P., then the ordered pair `(d, a_(50))` is equal to

A

(A,50+46A)

B

(A,50+45A)

C

(50,50+46A)

D

(50,50+45A)

Text Solution

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The correct Answer is:
A
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