Let me from a practical problem on direct proportion and try to solve it.

Let's prepare table as in from different proportion with 5,15, 10 and 30

A student can solve 2 out of 4 problems of mathematics, 3 out of 5 problem of physics, and 4 out of 5 problems of chemistry. There are equal number of books of math, physics, and chemistry in his shelf. He selects one book randomly and attempts 10 problems from it. If he solves the first problem, than the probability that the will be able to solve the second problem is

The probabilities of solving mathematical problem by Gopal, and Kesto are (1)/(3)" and " (1)/(4) respectively. Find the probability of not solving the problem.

A can solve 75% of the problems in this book and B can solve 70% . What is the probability that either A or B can solve a problem chosen at random ?

Let OP = 21 where O is the origin, if the direction radios of OP are proportional to 6, -2, 3, then the coordinates of P are -

Do ourselves - Let's find if the following numbers are in proportion or not. If they are in proportion, let's write all the possible proportions with them. (a) 3, 14, 4, 20

Let's frame the equations for the follwoing problem and solve them. frac(1)(5) th of a number taken away from frac(1)(4)th of its leaves a reaminder 2.

Let's frame the equations for the follwoing problem and solve them. When 6 is added to 6 times a number it becomes 8 timnes of itself.

The probabilities that three students Subhas, Monisha and Satabdi can solve a problem independently are p, q and r respectively. The chance that the problem is solved, is -

Let's frame the equations for the follwoing problem and solve them. The length of kumar's rectangular fielf is 1frac(1)(2) times of its breadth, the Perimeter of the land is 400m. Let's find the length and breadth of Kumar's land.