If P(E) = 0.05, what is the probability of 'not E"?

If P(E) = 0.10 , what is the probability of not E ?

If P( not E) = 0.25 , what is the probability of E ?

The probability that a student will pass the final examination in both English and Tamil is 0.5 and the probability of passing neither is 0.1 . If the probability of passing the English examination is 0.75, what is the probability of passing the Tamil examination ?

The probability that a student will pass the final examinatin in both English and Hindi is 0.5 and the probability of pasing neither is 0.1. If the probability of passing the English examination is 0.75. What is the probability of passing the Hindi examination?

Let E and F be two independent events. The probability that exactly one of them occurs is 11//25 and the probability of none of them occurring is 2//25. If P(T) denotes the probability of occurrence of the event T, then

A sample space consists of 9 elementary outcomes outcomes E_(1), E_(2) ,…, E_(9) whose probabilities are: P(E_(1))=P(E_(2)) = 0.09, P(E_(3))=P(E_(4))=P(E_(5))=0.1 P(E_(6)) = P(E_(7)) = 0.2, P(E_(8)) = P(E_(9)) = 0.06 If A = {E_(1), E_(5), E_(8)}, B= {E_(2), E_(5), E_(8), E_(9)} then (a) Calculate P(A), P(B), and P(A nn B). (b) Using the addition law of probability, calculate P(A uu B) . (c ) List the composition of the event A uu B , and calculate P(A uu B) by adding the probabilities of the elementary outcomes. (d) Calculate P(barB) from P(B), also calculate P(barB) directly from the elementarty outcomes of B.

Of the three independent event E_(1),E_(2) and E_(3) , the probability that only E_(1) occurs is alpha , only E_(2) occurs is beta and only E_(3) occurs is gamma . If the probavvility p that none of events E_(1), E_(2) or E_(3) occurs satisfy the equations (alpha - 2beta)p = alpha beta and (beta - 3 gamma) p = 2 beta gamma . All the given probabilities are assumed to lie in the interval (0, 1). Then, ("probability of occurrence of " E_(1))/("probability of occurrence of " E_(3)) is equal to

Ea n dF are two independent events. The probability that both Ea n dF happen is 1/12 and the probability that neither Ea n dF happens is 1/2 . Then, A) P(E)=1//3, P(F)=1//4 B) P(E)=1//4, P(F)=1//3 C) P(E)=1//6, P(F)=1//2 D) P(E)=1//2, P(F)=1//6