Two point charges `q_(1)` and `q_(2)` of magnitude + `10^(-8)` c and `-10^(-8)` c respectively are placed 0.1 m apart calculate the electric field between the point charges

Explanation

The electric flield vector `E_(1A)` at a due to the positive charge `q_(1)` point towards the right and has a magnitude
`E_(1A)=(9xx10^(9)Nm^(2)C^(2)xx(10^(-8)C))/(0.05 m)^(2)=3.6 xx10^(4) NC^(-1)` the electirc field vectors `E_(2A)` at a due to the negative charge `q_(2)` points of the total electric field `E_(A)` at A is
`E_(A)` is directed towards the right the electric field vector `E_(1B)` at B due to the positive charge `q_(1)` points towards the left and has a manitude
the magnitude of the total electric field at B is
`E_(B)` is directed towards the left
The magnitude of each electric field vector at point c due to charge `q_(1)` and `q_(2)` is
`E_( c)=E_(1c)` cos `(pi)/(3)+E_(2c)` cos `(pi)/(3)=9xx10^(3) Nc^(-1)`
`E_(c )` points towards the right