What is the freezing point of solution containing 3g of a non-volatile solute in 20g of water. Freezing point of pure water is 273K, `K_(f)` of water = 1.86 Kkg/mol. Molar mass of solute is 300 g/mol.
`T^(@)-T=K_(f)m`

Explanation

`m=(W_(2))/(M_(2)W_(1))`
`=(3)/(300xx20)xx1000`
`T^(@)-T=(1.86xx3xx1000)/(300xx20)=0.93K`
`T=273K-0.93K=272.07K`
`therefore" Freezing point of the solution = 272.07 K"`