0.2004 g of glucose gave on combustion 0.2940 g of `CO_(2)` and 0.1202 g of `H_(2)O`. Find the percentage composition.

Explanation

Weight of organic compound = 0.2004 g
Weight of carbon dioxide = 0.2940 g
Weight of water = 0.1202 g
Percentage of carbon
44 g of CO2 contains, carbon = 12 g
`"0.2940 g of "CO_(2)" contains, carbon"=(12xx0.2940)/(44)xx(100)/(0.2004)=40.01`
Percentage of hydrogen
18 g of `H_(2)O` contains, hydrogen = 2 g
0.1202 of `H_(2)O` contains, hydrogen `=(2xx0.1202)/(18)`
Percentage of hydrogen `=(2xx0.1202)/(18)xx(100)/(0.2004)=6.66`
Percentage of oxygen is therefore by difference,
`=[100-(40.01+6.66)]=53.33`