If .g. on the surface of the earth is `9.8 ms^(-2)` , find its value at a depth of 3200km (radius of the earth = 6400 km ) D

Explanation

epth , d= 3200km
The expression for the acceleration due to gravity at depth .d. is
`g_d = g |1 - d/R| rArr g_d = 9.8 |1- 3200/6400| rArr g_d = 4.9 ms^(-2)`