When a glass capillary tube is dipped in pure water, water rises to a height .h. in the tube. Capillary tube is pushed down till its height above the surface of water is `h^(1)[h^(1)lth]`. Find the relation between h and `h^(1)`.

Explanation

`h=(2Scostheta)/(rrhog)rArrhpropcostheta`
`h/h^(1)=(costheta_(1))/(costheta_(2))=(cos0^(@))/(costheta_(2))rArrcostheta_(2)=h^(1)/h`
`theta_(2)=cos^(-1)(h^(1)/h)`
In the special case angle of contact will change even if pair of solid & liquid are not changed.