A U tube is held such that the radius of one limb is r, and that of other is `r_(2)(r_(2)gtr_(1))`. A liquid of surface tension S, density `rho` and angle of contact zero is taken in the U tube. Then difference in the levels of the liquid in the two limbs is,

Explanation

Pressure at bottom of Ist limb
`p_(1)=h_(1)rhog+p_(0)-(2S)/r_(1)`
Pressure at bottom of 2nd limb `p_(2)=h_(2)rhog+p_(0)-(2S)/r_(2)`
Difference in the levels is
`(h_(1)-h_(2))=(2S)/(rhog)(1/r_(1)-1/r_(2))`