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A drop of water of volume V is pressed b...

A drop of water of volume V is pressed between the two glass plates so as to spread on area A. If T is the surface tension, the normal force required to separate the glass plates is :

Text Solution

Verified by Experts

Pressure difference = `T/R=T/(t//2)=(2T)/t`, Force = `(2T)/tA`
But V = At or t = `V/A,therefore"Force"=(2TA^(2))/V`
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