Home
Class 11
PHYSICS
A capillary tube of 0.5 mm bore stands v...

A capillary tube of 0.5 mm bore stands vertically in a wide vessel containing a liquid surface tension 30 dynes/cm. The liquid throughly wets the tube and has a specific gravity 0.8 calculate the rise of liquid in the tube `[g=10mS^(-2)]`

Text Solution

Verified by Experts

The correct Answer is:
3 cm
Promotional Banner

Topper's Solved these Questions

  • SURFACE TENSION

    AAKASH SERIES|Exercise NUMERICAL EXERCISE (LEVEL-2)|12 Videos

  • SURFACE TENSION

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|6 Videos

  • SURFACE TENSION

    AAKASH SERIES|Exercise SHORT ANSWER TYPE QUESTIONS|4 Videos

  • SIMPLE HARMONIC MOTION

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL - II)(PRACTICE SHEET (ADVANCED)) (INTEGER TYPE QUESTIONS)|3 Videos

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH SERIES|Exercise PRACTICE EXERCISE|99 Videos

Similar Questions

Explore conceptually related problems

Two capillary tubes of same material are dipped -vertically in the same liquid. If their radii are in the ratio of 2:3, the ratio of rise of liquid in the tubes is

A tube of 0.8 mm radius is dipped into a liquid with surface tension and density 6 xx 10^(-2) N/m and 900kg/ m^3 respectively. If the tube is kept vertical, the height of liquid risen in it will be (g=10ms^(-2))