Home
Class 11
PHYSICS
An ideal gas follows a process VT = cons...

An ideal gas follows a process VT = constant where V and T denote volume and absolute temperature. How does the temperature and volume depend on pressure ?

Text Solution

Verified by Experts

The correct Answer is:
`T alpha sqrt(P)" and "Vsqrt(P)=`constant
Promotional Banner

Topper's Solved these Questions

  • EXPANSION OF GASES

    AAKASH SERIES|Exercise NUMERICAL EXERCISE LEVEL - 2|13 Videos

  • ELEMENTS OF VECTORS

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWER|10 Videos

  • EXPANSION OF LIQUIDS

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|4 Videos

Similar Questions

Explore conceptually related problems

A gas follows a process TV^(n-1) = constant, where T = absolute temperature of the gas and V = volume of the gas. The bulk modulus of the gas in the process is given by

One mole of ideal gas goes through a process pV^3 = Constant , where p and V are pressure and volume, respectively. Let W be the work done by the gas as its temperature is increased by Delta T . The value of |W| is (R is the universal gas constant. )

Two gases A and B having same pressure p, volume V and absolute temperature T are mixed. If the mixture has the volume and temperature as V and T respectively, then the pressure of the mixture is

An ideal gas at 13^(@)C , is heated to double its volume at constant pressure. Find the final temperature of the gas.

If the pressure and absolute temperature of 4 litres of SO_2 gas are doubled, the volume of this gas would be