Two boys are standing at the ends A and B of a ground where AB = a. They boy at B starts runing in a direction perpendicular to AB with velocity `v_(1)`. The boy at A starts runing simultaneously with velocity v and catches the other in a time t, where t is

Options

A. `(a)/(sqrt(v^(2) + v_(1)^(2)))`
B. `(a)/(v+v_(1))`
C. `(a)/(v-v_(1))`
D. `sqrt((a^(2))/(v^(2) - v_(1)^(2)))`

Answer

D