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A wheel of perimeter 4pi m is rolling on...

A wheel of perimeter `4pi m` is rolling on a horizontal surface. The displacement of the point of contact of wheel and ground when the wheel completes one quarter of revolution is

A

`sqrt((pi + 2)^(2) + 4)` along `tan^(-1)""(2)/(pi)` with x-axis

B

`sqrt((pi -2)^(2) + 4)` along `tan^(-1)""(2)/(pi)` with x-axis

C

`sqrt((pi-2)^(2) + 4)` along `tan^(-1)""(2)/(pi-2)` with x-axis

D

`sqrt((pi + 2)^(2) + 4)` along `tan^(-1)""(2)/(pi-2)` with x-axis

Text Solution

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The correct Answer is:
C
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AAKASH SERIES-MOTION IN A PLANE -Practice Exercise
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