Three particles of identical masses . m . are kept at the vertices of an equilateral triangle of each side length .a. . Find the gravitational force of attraction on any one of the particles.

Explanation

Let `F_A and F_B` be the forces due to the masses at A and B on the mass at C .
Here `F_A = F_B`
Hence the Resultant force on the mass at C
`F = 2F_A"cos"theta//2 = 2.(Gm^2)/a^2 cos 30^@`
`= 2 xx(Gm^2)/a^2xxsqrt3/2 = sqrt3(Gm^2)/a^2`