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The escape velocities on the surface of...

The escape velocities on the surface of two planets of masses `m_1` and `m_2` and having same radius `v_1` and `v_2` respectively . Then

A

`v_1/v_2sqrt(m_1/m_2)`

B

`v_2/v_1=m_1/m_2`

C

`v_1/v_2=sqrt((m_2)/m_1)`

D

`v_1/v_2=((m_2)/m_1)^2`

Text Solution

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The correct Answer is:
A
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