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The escape velocities on the surface of ...

The escape velocities on the surface of two planets of masses `m_1 and m_2` and having the radius `r_1 and r_2 are v_1 and v_2` respectively, then

A

`v_1/v_2=(m_1r_1)/(m_2r_2)`

B

`v_2/v_1=(m_1r_1)/(m_2r_2)`

C

`v_2/v_1=sqrt((m_2r_1)/(m_1r_2))`

D

`v_2/v_1=sqrt((m_1r_1)/(m_2r_2))`

Text Solution

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The correct Answer is:
C
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