(a)Find `x+y+z`

(b)Find x+y+z+w

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0 .

Find the equation of the plane through the line of intersection of the planes x+y+z=1 " and " 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0 .

If x > 0, y > 0, z>0 and x + y + z = 1 then the minimum value of x/(2-x)+y/(2-y)+z/(2-z) is:

Statement -1 If x,y,z be real variables satisfying x+y+z=6 and xy+yz+z=8 , the range of variables x,y and z are identical. Statement -2 x+y+z=6 and xy+yz+zx=8 remains same if x,y,z interchange their positions.

Solve the equations x-y+3z=10,x-y-z=-2 and 2x+3y+4z=4 by matrix method.

The system of equations : x+y+z =6 x+2 y+3 z =10 x+2 y+lambda z =mu has no solution for

Find the equation of the plane passing through the line of intersection of the planes .x+ y+ z = 6 and 2x+ 3y+ 4z-5 = 0 and the point (1,1,1).

Find the equation of the plane through the intersection of the planes. 3x-y+2z=0 and x+y+z-2=0 and the point (2,2,1)