Obtain the product of `2,4y,8y^2,16y^3`

Use suitable identities of find the following products (y^2+3/2)(y^2-3/2)

Use the product [(1,-1,2),(0,2,-3),(3,-2,4)][(-2,-0,1),(9,2,-3),(6,1,-2)] to solve the system of equations x - y + 2z = 1 2y - 3z = 1 3x - 2y + 4z = 2

Area of the region bounded by x^(2)/16+y^(2)/9 =1 and the line x/4+y/3 =1 is

A nitrile X is treated with LiAIH_(4) to obtain compound Y (C_(2)H_(7)N) . In a separate reaction X is hydrolyzed in an acid medium to obtain Z. The product obtained after mixing Y and Z will be

Factorize the expressions and divide them as directed: 12xy(9x^2-16y^2):-4xy(3x+4y)

Find the centre of circle 5x^(2)+5y^(2)+4x-8y=16.

The radius of the circle 16 x^(2)+16 y^(2)-8 x+32 y-256=0 is

If the product of zeroes of polynomial f(y) =ay^3 - 6y^2 + 11y -6 is 4 then find the value of 'a'.

If the tangent to the ellipse x^2 +4y^2=16 at the point is normal to the circle x^2 +y^2-8x-4y=0 then theta is equal to