Show that `(4pq+3q)^2-(4pq-3q)^2`=`48pq^2`

Show that (9p-5q)^2+180pq=(9p+5q)^2

Multiply the binomials (2pq+3q^2) and (3pq-2q^2)

Subtract: 4pq-5q^2-3p^2 from 5p^2+3q^2-pq

Add the following: 2p^2q^2-3pq+4 , 5+7pq-3p^2q^2

Subtract 4p^2q-3pq+5pq^2-8p+7q-10 from 18-3p-11q+5pq-2pq^2+5p^2q

Add: 3p^2q^2-4pq+5,-10p^2q^2,15+9pq+7p^2q^2

Classify into monomials, boinomials and trinomials: 4p^2q-4pq^2

Find the common factors of the given terms 14pq, 28p^2q^2 .

If the p^(th) term of an A.P. is (1)/(q) and q^(th) term is (1)/( p) , show that the sum of pq terms is ((pq+1) )/(2) .

Factorize the expressions and divide them as directed: 5pq(p^2-q^2):-2p(p+q)