Using `a^2-b^2`=`(a+b)(a-b) find `(1.02)^2-(0.98)^2`

Using a^2-b^2 = (a+b)(a-b) find 12.1^2-7.9^2

Using a^2-b^2 = (a+b)(a-b) 'find' 51^2-49^2

Using a^2-b^2 = (a+b)(a-b) find 153^2-147^2

Using (x+a)(x+b) = x^2+(a+b)x+ab find 103 xx 98

Using (x+a)(x+b) = x^2+(a+b)x+ab find 5.1 xx 5.2

Find: 36-:0.2

|(1+a^(2)-b^(2), 2ab, -2b),(2a, 1 -a^(2)+b^(2),2a),(2b, -2a, 1-a^2-b^2)|=(1 + a^2 + b^2)^(3) .

a) Prove that int_(a)^(b)f(x)dx=int_(a)^(b)f(a+b-x)dx" and evaluate "int_(pi//6)^(pi//3)(dx)/(1+sqrt(tanx)) b) Prove that |{:(1+a^(2)-b^(2), 2ab, -2b), (2ab, 1-a^(2)+b^(2), 2a), (2, -2a, 1-a^(2)-b^(2)):}|=(1+a^(2)+b^(2))^(3)

Find the value of a,b,c and d from the equation: [(a-b,2a +c),(2a-b, 3c+d)]=[(-1,5),(0,13)]

Find (2a + 3b +5) ^(2) using identity.