Factorize: `(l+m)^2-(l-m)^2`

Factorize the following expressions: (l+m)^2-4lm [Hint:Expand(l+m)^2 first]

Factorize the expressions and divide them as directed: (m^2-14m-32):-(m+2)

Factorize two following expressions. 20 l^2m+30alm

Subtract: 3l(l-4m+5n) ,4l(10n-3m+2l)

Factorize the expressions: (lm+l)+m+1

The area of the quadrilateral formed by two pairs of lines l^(2) x^(2)-m^(2) y^(2)-n(l x+m y)=0 and l^(2) x^(2)-m^(2) y^(2)-n(L x-m y)=0 is

If m is the A.M. of two distinct real numbers l and n""(""l ,""n"">""1) and G1, G2 and G3 are three geometric means between l and n, then G1 4+2G2 4+G3 4 equals, (1) 4l^2 mn (2) 4l^m^2 mn (3) 4l m n^2 (4) 4l^2m^2n^2

Add the following: l^2 + m^2 , m^2+n^2 , 2lm+2mn+2nl

The line l x+m y-n=0 is a normal to the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 . then prove that (a^2)/(l^2)-(b^2)/(m^2)=((a^2-b^2)^2)/(n^2)