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If A = (2, (3sqrt3/2)) then coordinates...

If `A = (2, (3sqrt3/2))` then coordinates of C taken mirror image along x=0 is

A

`(-2, (3sqrt3)/2)`

B

`(-2- sqrt 6, (3sqrt3+1)/(2sqrt2))`

C

`(-2 sqrt 3, 3/2)`

D

`(0,3)`

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The correct Answer is:
To find the coordinates of point C, which is the mirror image of point A across the line x = 0, we will follow these steps: ### Step 1: Identify the coordinates of point A Point A is given as \( A = (2, \frac{3\sqrt{3}}{2}) \). ### Step 2: Understand the concept of mirror image across the line x = 0 The line x = 0 is the y-axis. When we take the mirror image of a point across the y-axis, the y-coordinate remains the same, while the x-coordinate changes sign. ### Step 3: Apply the mirror image concept to point A For point A: - The x-coordinate is 2. The mirror image across the y-axis will have the x-coordinate as \(-2\). - The y-coordinate remains unchanged, which is \(\frac{3\sqrt{3}}{2}\). ### Step 4: Write the coordinates of point C Thus, the coordinates of point C, the mirror image of point A across the line x = 0, will be: \[ C = (-2, \frac{3\sqrt{3}}{2}) \] ### Final Answer: The coordinates of point C are \((-2, \frac{3\sqrt{3}}{2})\). ---
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