If `log_(a) bc =x, log_(b) ca=y, log_( c)ab =z`, prove that `1/(x+1) + 1/(y+1) + 1/(z+1)=1`

If log_(a)bc = x, log_(b)ca = y and log_(c)ab = z , then the value of (1)/(x +1) + (1)/(y +1) + (1)/(z+1) is equal to

If log_(4)10=x,log_(2)20=y and log_(5)8=z prove that (1)/(x+1)+(1)/(y+1)+(1)/(z+1)=1

If x = log_(a) bc, y = log_(b) ca, z = log_(c) ab, then the value of (1)/(1 + x) + (1)/(1 + y) + (1)/(l + z) will be

If =1+log_(a)bc,y=1+log_(b)ca,z=1+log_(c)ab then prove that xyz=xy+yz+zx

If x=1+log_(a) bc, y=1+log_(b) ca, z=1+log_(c) ab , then (xyz)/(xy+yz+zx) is equal to

if =log_(a)(bc),y=log_(b)(ca) and z=log_(c)(ab) then (1)/(x+1)+(1)/(y+1)+(1)/(z+1)

If x = 1 + log_(a) bc, y = 1 + log_(b) ca, z = 1 + log_(c) ab, then xy + yz + zx =