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If the sum of first n terms of an A P is...

If the sum of first `n` terms of an `A P` is `c n^2,` then the sum of squares of these `n` terms is (2009) `(n(4n^2-1)c^2)/6` (b) `(n(4n^2+1)c^2)/3` `(n(4n^2-1)c^2)/3` (d) `(n(4n^2+1)c^2)/6`

A

`n(4n^2-1)c^2/6`

B

`n(4n^2+1)c^2/3`

C

`n(4n^2-1)c^2/3`

D

`n(4n^2+1)c^2/6`

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If the sum of first n terms of an AP is cn^(2) , then the sum of squares of these n terms is (2009)( a) (n(4n^(2)-1)c^(2))/(6) (b) (n(4n^(2)+1)c^(2))/(3) (c) (n(4n^(2)-1)c^(2))/(3) (d) (n(4n^(2)+1)c^(2))/(6)

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