`x = a (theta + sin theta), y = a (1 - cos theta)` find `dy/dx`

Find (d^2y)/(dx^2) in the following If x = a (theta + sin theta) , y = a(1 - cos theta) , find (d^2y)/(dx^2) at theta = pi/2

Find (dy)/(dx) in the following x = a(theta - sin theta), y = a (1 + cos theta)

Find (d^2y)/dx^2 , if x = a (theta - sin theta), y = a(1+cos theta)

If [x= a{theta - sin(theta)] and [y= a{1 - cos (theta)] find [d^2y/dx^2 at (theta = pi/2)

If x = a(cos theta + log tan(theta/2)), y = a sin theta find dy/dx at theta = pi/3

Find dy/dx if x = a(theta +sintheta), y = a(1-cos theta)

Find dy/dx when x= a (theta + sin theta), y = a(1+cos theta)

Find dy/dx when x=a (theta + sin theta), y = a(1 + cos theta)