Home
Class 12
MATHS
The cartesian equation of a line is 6x -...

The cartesian equation of a line is `6x - 2 = 3y + 1 = 2z - 2`. Find :(a) the direction-ratios of the line, and (b) vector equation of the line parallel to this line and· passing through the point (2, - 1, - 1).

Promotional Banner

Similar Questions

Explore conceptually related problems

Find equation of the line parallel to the line 3x-4y+ 2=0 and passing through the point (-2, 3).

Find the equation of the line parallel to the line 3x- 4y + 2 = 0 and passing through the point (- 2, 5).

The Cartesian equation of a line is (x-3)/2=(y+1)/(-2)=(z-3)/5 . Find the vector equation of the line.

The Cartesian equation of a line is (x+3)/2 = (y-5)/4 = (z+6)/2 . Find the vector equation for the line.

The cartesian equation of a line are 6x-2=3y+1=2z-2 . Find its direction ratios and also find the vector of the line.

Equation of the plane perpendicular to the line x/1=y/2=z/3 and passing through the point (2,3,4) is :

Find the equation of the line passing through the point (-1,1) and (2,4).

Write the equation of a line, parallel to the line (x-2)/-3=(y+3)/2=(z+3)/6 and passing through the point (1,2,3).

Find the vector and cartesian equations of the line that passes through : the points (1,2,3) and (2,-1,4).