The cartesian equations of a line are `3x + 1 = 6y - 2 = 1 - z`. Find the fixed point through which it passes, its direction-ratios and also its vector equation.

The Cartesian equation of a line is (x+3)/2 = (y-5)/4 = (z+6)/2 . Find the vector equation for the line.

The cartesian equation of a line are 6x-2=3y+1=2z-2 . Find its direction ratios and also find the vector of the line.

The cartesian equation of a line is 6x - 2 = 3y + 1 = 2z - 2 . Find :(a) the direction-ratios of the line, and (b) vector equation of the line parallel to this line and· passing through the point (2, - 1, - 1).

The Cartesian equation of a line is (x-3)/2=(y+1)/(-2)=(z-3)/5 . Find the vector equation of the line.

The cartesian equation of a line is (x-5)/3 = (y+4)/7 = (z-6)/2 . Write its vector form.

The cartesian equation of a line is (x-1)/(3)=(y-4)/(5)=(z-3)/(2) . Write its vector form.

If the cartesian equations of a line are : (3-x)/5=(y+4)/7=(2z-6)/4 , write the vector equation for the line.

Find the equation of the line parallel to the line 3x- 4y + 2 = 0 and passing through the point (- 2, 5).

Find equation of the line parallel to the line 3x-4y+ 2=0 and passing through the point (-2, 3).