Diagonal AC of a parallelogram ABCD bisects `/_A` (see the given figure), show that :
it bisects `/_C` also,

Diagonal AC of a parallelogram ABCD bisects /_A (see the given figure), show that ABCD is a rhombus.

AD and BC are equal perpendiculars to a line segment AB (see the given figure) Show that CD bisects AB.

The diagonal AC of a parallelogram ABCD intersects DP at the point Q, where ‘P’ is any point on side AB. Prove that CQ xx PQ = QA xx QD .

In quadrilateral ACBD. AC = AD and AB bisects angle A (see the given figure). Show that triangle ABC = triangle ABD . What can you say about BC and BD?

D is a point on side BC of triangle ABC such that AD = AC (see the given figure). Show that AB gt AD.

AB and CD are respec­tively the smallest and longest sides of a quadrilateral ABCD (see th e given figure). Show that angle A gt angle C and angle B gt angle D

In parallelogram ABCD, /_A-/_B= 30^(@) Then /_C= ………

In triangle ABC , the bisector AD of angle A is perpendicular to side BC (see the given figure). Show that AB = AC and triangle ABC is isosceles.

In parallelogram ABCD, 3/_A = 2 /_ B . Then, /_D=…….