Diagonal AC of a parallelogram ABCD bisects `/_A` (see the given figure), show that
ABCD is a rhombus.

Diagonal AC of a parallelogram ABCD bisects /_A (see the given figure), show that : it bisects /_C also,

The diagonal AC of a parallelogram ABCD intersects DP at the point Q, where ‘P’ is any point on side AB. Prove that CQ xx PQ = QA xx QD .

In quadrilateral ACBD. AC = AD and AB bisects angle A (see the given figure). Show that triangle ABC = triangle ABD . What can you say about BC and BD?

D is a point on side BC of triangle ABC such that AD = AC (see the given figure). Show that AB gt AD.

AD and BC are equal perpendiculars to a line segment AB (see the given figure) Show that CD bisects AB.

ABC is an isosceles triangle in which AB=AC bisects exterior angle PAC and CD||AB (See the given figure ). Show that ABCD is a parallelogram

In parallelogram ABCD, /_A-/_B= 30^(@) Then /_C= ………

AB and CD are respec­tively the smallest and longest sides of a quadrilateral ABCD (see th e given figure). Show that angle A gt angle C and angle B gt angle D

In an isosceles triangle ABC with AB = AC, D and E are points on BC such that BE = CD (see the given figure). Show that AD = AE.

In triangle ABC , the bisector AD of angle A is perpendicular to side BC (see the given figure). Show that AB = AC and triangle ABC is isosceles.