In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP= BQ (see the given figure) Show that:
`DeltaAPD ~= DeltaCQB`

In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP= BQ (see the given figure) Show that: DeltaAQB ~= DeltaCPD

In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP= BQ (see the given figure) Show that: AP= CQ

D is a point on side BC of triangle ABC such that AD = AC (see the given figure). Show that AB gt AD.

In an isosceles triangle ABC with AB = AC, D and E are points on BC such that BE = CD (see the given figure). Show that AD = AE.

ABCD is a parallelogram AP and CQ are perpendiculars drawn from vertices A and C on diagonal BD (see figure) show that (i) DeltaAPB ~= DeltaCQD (ii) AP = CQ

ABC and DBC are two isosceles triangles on the same base BC (see the given figure). Show that angle ABD = angle ACD .

Ray 1 is the bisector of an angle angle A and B is any point on I. BP and BQ are perpendiculars from B to the arms of angle A (see the given figure). Show that: (i) triangleAPB=triangleAQB (ii) BP = BQ or B is equidistant from the arms of angleA

Diagonal AC of a parallelogram ABCD bisects /_A (see the given figure), show that ABCD is a rhombus.

Diagonal AC of a parallelogram ABCD bisects /_A (see the given figure), show that : it bisects /_C also,

In right triangle ABC, right angled at C, M is the midpoint of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see the given figure). Show that: (i) triangle AMC = triangleBMD (ii) angle DBC is a right angle (iii) triangleDBC = triangleACB (iv) CM=1/2 AB