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In a right trianlge ABC right angled at C, P and Q are the points on the sides CA and CB respectively which divide these sides in the ratio 2 : 1. Prove that `9(AQ^(2)+BP^(2))= 13AB^(2)`.

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The correct Answer is:
`9(AQ^(2)+BP^(2))= 13AB^(2)`
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