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In triangleABC, AD, BE, CF are the media...

In `triangleABC`, AD, BE, CF are the medians. Prove that, `4(AD^(2)+BE^(2)+CF^(2))= 3(AB^(2)+BC^(2)+AC^(2))`.

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The correct Answer is:
`4(AD^(2)+BE^(2)+CF^(2))= 3(AB^(2)+BC^(2)+AC^(2))`
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