Home
Class 10
MATHS
In the given figure, ABC and DBC are two...

In the given figure, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that `(ar(ABC))/(ar(DBC))= (AO)/(DO)`.

Text Solution

Verified by Experts

The correct Answer is:
`(ar(ABC))/(ar(DBC))= (AO)/(DO)`
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    KUMAR PRAKASHAN|Exercise EXERCISE 6.5|23 Videos
  • TRIANGLES

    KUMAR PRAKASHAN|Exercise EXERCISE 6.6|15 Videos
  • TRIANGLES

    KUMAR PRAKASHAN|Exercise EXERCISE 6.3|27 Videos
  • SURFACE AREAS AND VOLUMES

    KUMAR PRAKASHAN|Exercise TEST YOUR SKILLS|5 Videos

Similar Questions

Explore conceptually related problems

In the given figure, ABC and DBC are two triangles on the same base BC. Prove that (ar(ABC))/(ar(DBC))= (AO)/(DO) .

In the figure, ΔABC and ΔABD are two triangles on the same base AB. If line segment CD is bisected by bar(AB) at O, show that ar (DeltaABC) = ar (DeltaABD).

In the given figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that : (CA)/(PA)=(BC)/(MP)

ABC and DBC are two isosceles triangles on the same base BC (see the given figure). Show that angle ABD = angle ACD .

triangle ABC and triangle DBC are isosceles triangles on the same base BC. Prove that line AD bisects BC at right angles

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

In the given figure, angle B lt angle A and angle C lt angle D . Show that AD lt BC.

In the given figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that : DeltaABC ~ DeltaAMP

In the given figure, AC = AE, AB = AD and angle BAD = angle EAC . Show that BC = DE.

In the given figure ABC is a right triangle and right angled at B such that /_BCA = 2/_BAC. Show that hypotenuse AC = 2BC.