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The vertices of a Delta ABC are A(4,6), ...

The vertices of a `Delta ABC` are A(4,6), B(1,5) and C(7,2) . A line is drawn to intersect sides AB and AC at D and E respectively, such that `(AD)/(AB) = (AE)/(AC) = (1)/(4)` . Calculate the area of the `Delta ADE` and compare it with the area of `Delta ABC` . (Recall Theorem 6 . 2 and Theorem 6 . 6)

Text Solution

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The correct Answer is:
`(15)/(32)` sq units and the ratio of areas of `Delta ADE and Delta ABC ` is 1 : 16
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