In which of the following reactions `H_(2)O_(2)` does not act as an reducing agent ?

Options

A. `I_(2)+H_(2)O_(2)+2OH^(-) to 2I^(-) +2H_(2)O+O_(2)`
B. `PbS+4H_(2)O_(2) to PbSO_(4) +4H_(2)O`
C. `2KMnO_(4)+3H_(2)O_(2) to 2MnO_(2) +2KOH +2H_(2)O+3O_(2)`
D. `HOCl+H_(2)O_(2) to H_(3)O^(+) +Cl^(-)+O_(2)`

Answer

B

Explanation

Oxygen of `H_(2)O_(2)` (-1) is coverted to (-2) of `H_(2)O`. There is reduction. `H_(2)O_(2)` is oxidising agent.
(A), (B), (D) : `underset(2(-1))underset(" "darr)(H_(2)O_(2))to underset(2(O))underset(uarr)(O_(2))+2e`...Oxidation