The momentum of a body increased doubled .What is the percentage of increment in its kinetic energy ?

Explanation

`K = 1/mv^(2) = (p^(2))/(2m) " " …(1)`
`K = (p^(2))/(2m) " "….(2)`
`p. =2p `
` :. K = (4p^(2))/(2m)`
` :. K . = 4K `
Increase in kinetic energy = `(DeltaK)/K xx100`
`= (3K)/K xx 100`
= 300 %