If the kinetic energy of the body is increased by 300 % then , the increase in momentum will be `……`

Options

A. 1
B. 1.5
C. 2
D. 1.75

Answer

A

Explanation

Initial kinetic energy `E_(1)=E`
When kinetic energy increases 300 % then
Now kinetic energy
`E_(2)=E+ 2E = 4E`
Now `E = (p^(2))/(2m)`
` :. P prop sqrt€ ` (m = constant)
`:. (p_(2))/(p_(1))=sqrt((E_(2))/(E_(1)))=sqrt((4E)/E)`
` :. p_(2) =2p_(1) =p_(1)+p_(1)`
` :. ` Momentum increased by 100 %