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Two bodies of masses m(1) and m(2) have ...

Two bodies of masses `m_(1) and m_(2)` have same linear momentum . The ratio of their kinetic energies `(E_(1))/(E_(2))` will be `………`

A

`sqrt(m_(1)):sqrt(m_(2))`

B

`m_(1):m_(2)`

C

`m_(2):m_(1)`

D

`m_(12):m_(22)`

Text Solution

Verified by Experts

The correct Answer is:
C
Kinetic energy `E =(p^(2))/(2m)`
` :. E prop 1/(2m) , ` p = constant
` :. (E_(1))/(E_(2)) =(m_(2))/(m_(1)) =m_(2) :m_(1)`
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