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Find the value of each of the following ...

Find the value of each of the following polynomials at the indicated value of variables :
`q(y) = 3y^(3) - 4y + sqrt(11)` at y = 2.

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The correct Answer is:
`16+sqrt(11)`
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Find the value of each of the following polynomials at the indicated value of variables : p(t) = 4t^(4) + 5t^(3) - t^(2) + 6 at t = a.

Find the vaoue of each of the folllowing polynomials for the indicated value of variables: (i) p(x) = 4x ^(2) - 3x + 7 at x =1 (ii) q (y) = 2y ^(3) - 4y + sqrt11 at y =1 (iii) r (t) = 4t ^(4) + 3t ^(3) -t ^(2) + 6 at t =p, t in R (iv) s (z) = z ^(3) -1 at z =1 (v) p (x) = 3x ^(2) + 5x -7 at x =1 (vii) q (z) = 5z ^(3) - 4z + sqrt2 at z =2

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KUMAR PRAKASHAN-POLYNOMIALS-Multiple Choice Questions (MCQs)
  1. Find the value of each of the following polynomials at the indicated v...

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  2. The value of p(x) = x^(3) + x^(2) - 3x-3 at x = -1 is …… .

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  3. For the polynomial p(x), if p(2) = 0, then ……… is a factor of p(x).

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  4. Dividing 2x^(3) + 6x^(2) + x + 5 by (x+3), the remainder is ……….. .

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  5. ……….. should be substracted from x^(3) + 3x^(2) + 2x + 10, so that the...

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  6. …………..should be added to x^(3) - 5x^(2) + x-8, so that the result is e...

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  7. ……….. is one of the zeros of the polynomial x^(3) - 6x^(2) + 2x -12.

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  8. If x+3 is a factor of x^(3) +6x^(2) + 11x + k, then k =.

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  9. ……….. Should be added to x^(2) - 8, so that the result is exactly divi...

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  10. Find the value of k, if x-1 is a factor of 4x^(3) + 3x^(2) - 4x + k.

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  11. …………is one of the factors of 2x^(4) + x^(3) - 14 x^(2) - 19x - 6.

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  12. When x^(3) + 64 is divided by x+4, the quotient is ……… .

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  13. x^(3) + 3x^(2) + 3x + 2 = (x+2) (………)

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  14. The factors of x^(2) - x-12 are ………. .

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  15. The factors of x^(2) - 100 are ……….. .

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  16. x^(2) - 2 + (1)/(x^(2)) = …………

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  17. If x^(2) + mx - 28 = (x-7)(x+4), then m = ……… .

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  18. 105 xx 95

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  19. (110)^(3) = ………..

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  20. Evaluate each of the following using proper identity : 15^(3) - 9^...

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  21. If x + 3 is one of the factors x^(3) + 2x^(2) - ax - 18 then a = ……… .

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