Home
Class 9
MATHS
In parallelogram ABCD , diagonals AC and...

In parallelogram ABCD , diagonals AC and BD intersect at point O. Point P lies on line segment BO. Prove that (1) ar(ADO)=ar(CDO)
(2)ar(ABP)=ar(CBP)

Promotional Banner

Topper's Solved these Questions

  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    KUMAR PRAKASHAN|Exercise Sum to Enrich Remember|4 Videos

  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    KUMAR PRAKASHAN|Exercise Skill Testing Exercise|12 Videos

  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    KUMAR PRAKASHAN|Exercise Exercise 9.3|10 Videos

  • BOARD'S SAMPLE QUESTION PAPERS (QUESTION PAPER 1 : FOR THE FIRST TEST)

    KUMAR PRAKASHAN|Exercise Section D (Solve the following) |4 Videos

Similar Questions

Explore conceptually related problems

ABCD is a parallelogram. The diagonals AC and BD intersect each other at ‘O’. Prove that ar(DeltaAOD) = ar(DeltaBOC) . (Hint: Congruent figures have equal area)

In triangleABC , point D lies on side BC. E is the midpoint of AD. Prove that, ar(EBC)= 1/2 ar(ABC)

In the figure, diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Prove that ar(DeltaAOD) = ar(Delta BOC).

ABCD is parallelogram and ABEF is a rectangle and DG is perpendicular on AB. Prove that (i) ar (ABCD) = ar(ABEF) (ii) ar (ABCD) = AB xx DG

ABCD is a parallelogram. AC and BD are the diagonals intersect at O. P and Q are the points of tri section of the diagonal BD. Prove that CQ" ||" AP and also AC bisects PQ (see figure).

In triangleABC , medians AC, BE and CF intersect at point G. Prove that ar(GAB)=ar(GBC)=ar(GCA)= 1/3 ar(ABC).

The diagonal AC of a parallelogram ABCD intersects DP at the point Q, where ‘P’ is any point on side AB. Prove that CQ xx PQ = QA xx QD .

ABCD is a trapezium in which AB||DC and its diagonals intersects each other at the point O. Show that (AO)/(BO)=(CO)/(DO) .

PQRS and ABRS are parallelograms and X is any point on the side BR. Show that (i) ar(PQRS) = ar(ABRS) (ii) ar(DeltaAXS) =1/2 ar(PQRS)

In quadrilateral ABCD, AM and CN are altitudes on diagonal BD drawn from A and C respectively .Prove that ar(ABCD)= 1/2 BD(AM+CN)