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The escape velocity for a body projected...

The escape velocity for a body projected vertically upwards from the surface of earth is `11 kms^(-1)`. If the same body is projected at an angle of `45^(@)` with the vertical, the escape velocity will be

A

`11sqrt(2)kms^(-1)`

B

`22 kms^(-1)`

C

`11kms^(-1)`

D

`11//sqrt(2) kms^(-1)`

Text Solution

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The correct Answer is:
C
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AAKASH SERIES-GRAVITATIONAL-EXERCISE-2
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