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A force F is given by F at + bt^(2) wher...

A force F is given by F at + `bt^(2)` where t is time. What are dimensions of 'a' and 'b'?

A

`MLT^(-3)` and `ML^2T^4`

B

`MLT^(-3)` and `MLT^(-4)`

C

`MLT^(-1) ` and `MLT^0`

D

`MLT^(-4) ` and `MLT^1`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • If the force is given by F = at + bt^(2) with t as time. The dimensions of a and b are

    A
    `[MLT^(-4)], [MLT^(-2)]`
    B
    `[MLT^(-3)], [MLT^(-4)]`
    C
    `[ML^(2)T^(-3)], [ML^(2)T^(-2)]`
    D
    `[ML^(2)T^(-3)], [ML^(3)T^(-4)]`
  • For a body in a uniformly accelerated motion, the distance of the body from a reference point at time 't' is given by x= a t + bt^(2) + c where a, b, c are constans. The dimensions of 'c' are the same as those of (A) x (B) at (C ) bt^(2) (D) a^(2)//b

    A
    A
    B
    A &B
    C
    A, B & C
    D
    A, B, C & D
  • For a body in a uniformly accelerated motion, the distance of the body from a reference point at time t is given by x=al+ bt^(2) + C where a,b, c are constants. The dimensions of 'c' are the same as those of (a) x (b) at (c) bt^(2) (d) a^(2) //b

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    B
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    C
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    D
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