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A stone is dropped into a well and the s...

A stone is dropped into a well and the sound of splash is heard after `5.3sec`. If the water is at a depth of `122.5m` from the ground, the velocity of sound in air is

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If `t_(1)` is the time taken by stone to reach the ground and `t_(2)` the time taken by sound to go up, then `t_(1)+t_(2)=5.33`
Since `s=ut+(1)/(2)at^(2) 122.5=0t+(1)/(2)xx9.8xxt_(1)^(2)`
`therefore t_(1)^(2)=(245)/(9.8)=(2450)/(98)=25 therefore t_(1)=5s therefore t_(2)=0.33s`
Velocity of sound = `therefore t_(1)^(2)=(245)/(9.8)=(2450)/(98)=25 therefore t_(1)=5s therefore t_(2)=0.33s`
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