Home
Class 11
PHYSICS
A particle moves along the X-axis as x=u...

A particle moves along the X-axis as `x=u(t-2)+a(t-2)^(2)`
a) the initial velocity of the particle is u
b) the acceleration of the particle is 2a
c) at `t=2s` particle is at the origin

A

a & b are correct

B

b & c are correct

C

a & c are correct

D

c & d are correct

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle moves along the X-axis as x=u(t-2)+a (t-2)^(2) a)the initial velocity of the particle is u b)]the acceleration of the particle is a c)the acceleration of the particle is 2a d)at t=2 s particle is at the origin

A particle moves along the X-axis as x=u(t-2)+a(t-2)^2 (a) the initial velocity of the particle is u (b) the acceleration of the particle is a (c) the acceleration of the particle is 2a (d) at t = 2 s particle is at the origin

A particle moves along the X-axis with velocity v = (dx)/(dt)=f(x) then the acceleration of the particle is

A particle moves along a line according to the law s=t^4-5t^2+8 . The intial velocity is

A particle is moving along a line according s= f(t) = 8t + t^3 . Find the initial velocity

A particle moves along a straight line and its velocity at a distance 'x' from the origin is ksqrt(a^(2) - x^(2)) . Then accelertion of the particle is

A particle moves along a line by s = (1)/(3)t^(2) + 8t + 5 , it changes its direction when

A particle moving according to the law s=6t-1/2t^3 . At what time its velocity vanishes ?