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A particle is moving in a circle of rad...

A particle is moving in a circle of radius R = 1m with constant speed v = 4 m/s. The ratio of the displacement to acceleration of the foot of the perpendicular drawn from the particle onto the diameter of the circle is

A

`1/16 s^(2)`

B

`1/2s^(2)`

C

`2s^(2)`

D

`16s^(2)`

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The correct Answer is:
A
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AAKASH SERIES-OSCILLATIONS-EXERCISE II
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  7. A particle is vibrating in SHM with an amplitude of 4 cm. At what disp...

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  9. If a body of mass 36 gm moves with S.H.M. of amplitude A = 13 cm and p...

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  10. For a body in S.H.M the velocity is given by the relation v = sqrt(144...

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  12. Acceleration displacement graph of a particle executing S.H.M is as sh...

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  13. The displacement of a particle from its mean position (in meter) is gi...

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  14. Two SHMs are represented by the equations y(1)=10sin(3pit+pi//4) and...

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  15. A particle of mass 4 gm is moving simple harmonically with a period 8 ...

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  16. Which of the following quantities are always positive in a S H M

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  17. For a particle executing SHM. The KE .K. is given by K = K(0) cos^(2) ...

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  18. A body is executing simple harmonic motion. At a displacement x its po...

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  19. The displacement of two identical particles executing SHM are represen...

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  20. A particle of mass m executes SHM with amplitude .a. and frequency .v....

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