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m grams of a gas of a molecular weight M...

m grams of a gas of a molecular weight M is flowing in an isolated tube withvelocity 2V. If the gas flow is suddenly stopped the rise in its temperature is , `(gamma`=ratio of specific heats, R=universal gas constant, J=Mechanical equilent of heat)

A

`( 2M v^(2) ( gamma-1))/( RJ)`

B

`( mv^(2) ( gamma - 1))/( M2RJ)`

C

`( mv^(2) gamma)/( 2RJ)`

D

`( Mv^(2) gamma)/( 2 RJ)`

Text Solution

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The correct Answer is:
A
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