A block of mass 1kg lies on a horizontal surface in a truck. The coefficient of friction between the block and the surface is 0.5. if the acceleration of the truck is `6ms^(-2)`, find the acceleration of the block.

Explanation

`m=1 kg, mu=0.5, a=6ms^(-2), g=10ms^(-2)` Acceleration of the block with respect to the truck=`a-mug Acceleration of the block will respect to ground `=mug=5m//s^(2)`